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500-7x+0.02x^2=0
a = 0.02; b = -7; c = +500;
Δ = b2-4ac
Δ = -72-4·0.02·500
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-3}{2*0.02}=\frac{4}{0.04} =100 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+3}{2*0.02}=\frac{10}{0.04} =250 $
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